`Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt` cell reaction will be endergonic ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. `p_(1)=1 atm`

`Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt` cell reaction will be

1.	`Pt(Cl_(2))(p_(1))\|HCl(0.1M)\|(Cl_(2))(p_(2)),Pt` cell reaction will be endergonic ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. `p_(1)=1 atm`
Answer» Correct Answer - c Cell is spontaneous when `p_(2)(` cathode `)gtp_(1)(` anode `)` At anode `: 2Cl^(c-)(0.1M) rarr Cl_(2)(p_(1))+2e^(-)` At cathode `: Cl_(2)(p_(2))+2e^(-) rarr 2 C l^(c-)(0.1M)` `ulbar(Cell reaction : Cl_(2)(p_(2))rarr Cl_(2)(p_(1)))` `C_(cell)=E^(c-)._(cell)-(0.059)/(2)log.(p_(1))/(p_(2))` `=0+(0.059)/(2)log `(p_(2))/(p_(1))` `E_(cell)gt0` if `p_(2)gtp_(1)`.

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`Pt(Cl_(2))(p_(1))|HCl(0.1M)|(Cl_(2))(p_(2)),Pt` cell reaction will be endergonic ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. `p_(1)=1 atm`

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