प्रत्येक स्थिति में x का मा�

1.	प्रत्येक स्थिति में x का मान बताइएः(i) \(\frac{2}{3}\times x=1\)(ii) \((\frac{-3}{4}) + x =0\)(iii) \(x \times(\frac{-5}{4})=1\)(iv) \(x \times(\frac{-6}{-7})=1\)(v) \((\frac{-5}{4})\times(\frac{4}{-5})=x\)(vi) \((\frac{-7}{6})+\frac{7}{6}=x\)
Answer» (i) \(\frac{2}{3}\times x=1\) ⇒ \(x=\frac{3}{2}\) (ii) \((\frac{-3}{4}) + x =0\) ⇒ \(x=0-(\frac{-3}{4})\) ⇒ \(x=\frac{3}{4}\) (iii) \(x \times(\frac{-5}{4})=1\) ⇒ \(x=1\div(\frac{-5}{4})=1\times(\frac{4}{-5})\) ⇒ \(x=\frac{-4}{5}\) (iv) \(x \times(\frac{-6}{-7})=1\) ⇒ \(x=1\div(\frac{-6}{-7})=1\times(\frac{-7}{-6})\) ⇒ \(x=\frac{7}{6}\) (v) \((\frac{-5}{4})\times(\frac{4}{-5})=x\) ⇒ \(x=\frac{-20}{-20}=1\) (vi) \((\frac{-7}{6})+\frac{7}{6}=x\) ⇒ \(x=0\)

प्रत्येक स्थिति में x का मान बताइएः(i) \(\frac{2}{3}\times x=1\)(ii) \((\frac{-3}{4}) + x =0\)(iii) \(x \times(\frac{-5}{4})=1\)(iv) \(x \times(\frac{-6}{-7})=1\)(v) \((\frac{-5}{4})\times(\frac{4}{-5})=x\)(vi) \((\frac{-7}{6})+\frac{7}{6}=x\)

Answer»

(i) \(\frac{2}{3}\times x=1\)

⇒ \(x=\frac{3}{2}\)

(ii) \((\frac{-3}{4}) + x =0\)

⇒ \(x=0-(\frac{-3}{4})\)

⇒ \(x=\frac{3}{4}\)

(iii) \(x \times(\frac{-5}{4})=1\)

⇒ \(x=1\div(\frac{-5}{4})=1\times(\frac{4}{-5})\)

⇒ \(x=\frac{-4}{5}\)

(iv) \(x \times(\frac{-6}{-7})=1\)

⇒ \(x=1\div(\frac{-6}{-7})=1\times(\frac{-7}{-6})\)

⇒ \(x=\frac{7}{6}\)

(v) \((\frac{-5}{4})\times(\frac{4}{-5})=x\)

⇒ \(x=\frac{-20}{-20}=1\)

(vi) \((\frac{-7}{6})+\frac{7}{6}=x\)

⇒ \(x=0\)