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प्रथम 10 संख्याओ के वर्ग का औसत ज्ञात करेA. 35.5B. 36C. 37.5D. 38.5 |
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Answer» Correct Answer - D `=(n(n+1)(2n+1))/(6n)=((n+1)(2n+1))/6` According to question Avg. of square of first ten natural number is `=((10+1)(20+1))/6` `=(11xx21)/6` =38.5 |
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