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Provee fig, AD is bisector of ZA. Show that AB > BD. |
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Answer» Given :AD is the bisector of ∠A of triangle ABC. Hence, ∠DAB=∠DAC∠BDA is the exterior angle of the ∆DAC. Hence, ∠BDA> ∠DACor ∠BDA > ∠DAB Since ,∠DAC=∠DAB → AB > BD[:• In a triangle sides opposite to greater angle is greater.] |
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