1.

Provee fig, AD is bisector of ZA. Show that AB > BD.

Answer»

Given :AD is the bisector of ∠A of triangle ABC.

Hence, ∠DAB=∠DAC∠BDA is the exterior angle of the ∆DAC.

Hence, ∠BDA> ∠DACor ∠BDA > ∠DAB Since ,∠DAC=∠DAB

→ AB > BD[:• In a triangle sides opposite to greater angle is greater.]



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