1.

Proved that g(a2)=g(a-2)​

Answer»

ANSWER:

A

2

=a+2d=a+

3

2(b−a)

=

3

a+2b

So, 2A

1

−A

2

=2(

3

2a+b

)−(

3

a+2b

)=a

and 2A

2

−A

1

=2(

3

a+2b

)−(

3

2a+b

)=b

Therefore,

(2A

1

−A

2

)(2A

2

−A

1

)=AB

(2A

1

−A

2

)(2A

2

−A

1

)=G

2

A

2

=a+2d=a+

3

2(b−a)

=

3

a+2b

So, 2A

1

−A

2

=2(

3

2a+b

)−(

3

a+2b

)=a

and 2A

2

−A

1

=2(

3

a+2b

)−(

3

2a+b

)=b

Therefore,

(2A

1

−A

2

)(2A

2

−A

1

)=ab

(2A

1

−A

2

)(2A

2

−A

1

)=G

2

Step-by-step EXPLANATION:


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