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Prove tht a cyclic parallelogram is a rectangle better not spamヽ(`Д´)ノ |
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Answer»
ABCD is a CYCLIC parallelogram. To prove, ABCD is a rectangle. Proof: ∠1+∠2=180° ...Opposite angles of a cyclic parallelogram Also, Opposite angles of a cyclic parallelogram are equal. Thus, ∠1=∠2 ⇒∠1+∠1=180° ⇒∠1=90° One of the interior angle of the parallelogram is right angled. Thus, ABCD is a rectangle. ae gavar ITNA bhi NAHI AATA kya┐( ˘_˘)┌
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