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Prove thefollowing identity: sin cube A + cos cube A divided by sin A + cos A= 1 - sin A cos A |
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Answer» (sin^3A+Cos^3A) /(SINA+ COSA) =(sinA+cosA) (sin^2A+cos^2A-sinAcosA) /(sinA+cosA) =1-sinAcosA |
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