1.

Prove the following:  tan (π/4+θ) = 1+tanθ/1-tanθ

Answer»

L.H.S = tan(π/4+θ)

\(\frac{tan\frac{\pi}{4}+tan \theta}{1-tan\frac{\pi}{4}tan\theta}\)

\(\frac{1+tan\theta}{1-(1)tan\theta}\)

=\(\frac{1+tan\theta}{1-tan\theta}\)

=RHS



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