Saved Bookmarks
| 1. |
Prove the following: tan (π/4+θ) = 1+tanθ/1-tanθ |
|
Answer» L.H.S = tan(π/4+θ) = \(\frac{tan\frac{\pi}{4}+tan \theta}{1-tan\frac{\pi}{4}tan\theta}\) = \(\frac{1+tan\theta}{1-(1)tan\theta}\) =\(\frac{1+tan\theta}{1-tan\theta}\) =RHS |
|