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Prove the following as irrational number 4-3√2 and with process plz help |
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Answer» ONG>Answer: Let us assume the contrary, that 4− 3
is rational. That is, we can FIND co-prime a and b (b =0) such that 4− 3
= b a
. Therefore 4− b a
= 3
. Rearranging this equation, we get 3
=4− b a
= b 4b−a
Since a and b are integers, we get b 4b−a
is rational, and so 3
is rational. But this CONTRADICTS the fact that 3
is IRRATIONAL, This contradicts the fact that 3
is irrational. This contradiction has arisen because of our incorrect ASSUMPTION that 4- 3
is rational. so, we conclude that 4− 3
is irrational |
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