1.

Prove the following ( 1 + tanA . tanB )² + ( tanA - tanB )² = sec²A . sec² B​

Answer»

(tanA−tanB)

2

+(1+tanAtanB)

2

=TAN

2

A+tan

2

B−2tanAtanB+1+tan

2

ATAN

2

B+2tanAtanB

=tan

2

A+tan

2

B+1+tan

2

(A)tan

2

(B)

=tan

2

(A)[1+tan

2

(B)]+[1+tan

2

(B)]

=(1+tan

2

(B))(1+tan

2

(A))

=SEC

2

B.sec

2

A


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