1.

Prove the exterior of regular quadrilateral is 3/4 of interior angle of regular hexagon​

Answer»

Step-by-step explanation:

so interior sum of interior ANGLES of regular QUARDILATERAL is

( 4 -2) × 180

= 360

and each angle is equal to

= 360 / 4 (as there are 4 angles)

= 90

its exterior angle is

= 180 - 90 = 90

now sum of angles of regular hexagon

= (6 - 2) ×180

= 4× 180

= 720

and each angle is equal to

= 720/6 (as there are 6 angle )

= 120

now 3/4 of interior angles of regular hexagon

= 120×(3/4)

= 30×3 = 90

and 90 is exterior angle of regular quardilateral

so this PROVES that exterior angle of regular quardilateral is 3/4 of interior angles of regular hexagon

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