Prove that1+sec A/ sec A=sin² A / 1-cos A

1.	Prove that1+sec A/ sec A=sin² A / 1-cos A
Answer» ong>Step-by-step explanation: LHS = ( 1 + SECA )/secA = ( 1 + 1/COSA ) / ( 1/cosA ) = [ ( CosA + 1 ) / cosA ] / ( 1/ cosA ) = Cos A + 1 = ( 1 + cosA ) ( 1 - cosA ) / ( 1 - cosA ) = ( 1 - cos² A ) / ( 1 - cosA ) = Sin² A / ( 1 - cosA ) = RHS

Answer»

ong>Step-by-step explanation:

LHS = ( 1 + SECA )/secA

= ( 1 + 1/COSA ) / ( 1/cosA )

= [ ( CosA + 1 ) / cosA ] / ( 1/ cosA )

= Cos A + 1

= ( 1 + cosA ) ( 1 - cosA ) / ( 1 - cosA )

= ( 1 - cos² A ) / ( 1 - cosA )

= Sin² A / ( 1 - cosA )

= RHS

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Prove that1+sec A/ sec A=sin² A / 1-cos A​

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Prove that1+sec A/ sec A=sin² A / 1-cos A