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Prove that when projectiles are thrown at complementary angles, the range is equalDONOT SPAM...I NEED THE PROPER PROOF WITH PROPER EXPLANATION!!!PLEASE......DO IT ASAP

Answer»

show that for TWO COMPLEMENTARY angles of PROJECTION of a projectile thrown with thw same VELOCITY. the horizontal ranges are equal. The range is maximum when sin2θ is maximum. So, for two angles, θ and 90 – θ the range of the projectile will be same.

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