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Prove that when projectiles are thrown at complementary angles, the range is equalDONOT SPAM...I NEED THE PROPER PROOF WITH PROPER EXPLANATION!!!PLEASE......DO IT ASAP |
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Answer»
show that for TWO COMPLEMENTARY angles of PROJECTION of a projectile thrown with thw same VELOCITY. the horizontal ranges are equal. The range is maximum when sin2θ is maximum. So, for two angles, θ and 90 – θ the range of the projectile will be same.
Your few explanation is in the picture |
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