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Prove that when projectiles are thrown at complementary angles, the range is equal DONOT SPAM...I NEED THE PROPER PROOF WITH PROPER EXPLANATION!!! PLEASE......DO IT ASAP |
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Answer» > show that for two complementary ANGLES of projection of a projectile thrown with thw same velocity. the horizontal RANGES are equal. The range is MAXIMUM when sin2θ is maximum. So, for two angles, θ and 90 – θ the range of the projectile will be same.
Your few EXPLANATION is in the picture |
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