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Prove that v3 is irrational. |
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Answer» Given √3 is irrational number. Let √3 = a / b wher a,b are integers b ≠ 0we also suppose that a / b is written in the simplest form Now √3 = a / b ⇒ 3 = a²/ b² ⇒ 3b²= a² ∴ 3b²is divisible by 3 ⇒ a²is divisible by 3 ⇒ a is divisible by 3 ∴ let a = 3c a²= 3c² ⇒ 3b²= 9c² ⇒b²= 3c² ∴ 3c² is divisible by 3 ∴ b² is divisible by 3 ∴ b is divisible by 3 ∴a are b are divisible by 3this contradicts our supposition that a/b is written in the simplest formHence our supposition is wrong ∴ √3 is irrational number. |
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