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Prove that triangle PQR congruent to triangle PSR and also prove that QR=PS |
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Answer» In ∆PQR, ∆PSR ANGLE PQR= ANGLE PSR (EACH OF 90°) PR=PR (COMMON) PS=PQ (GIVEN) .'. ∆PQR =~ ∆PSR BY SIDE ANGLE SIDE CONGRUENCY(SAS) RULE QR=RS BY CPCT |
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