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prove that time period of a simple pendulum on the surface of the moon is 2.45 times greater than on the surface of the earth |
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Answer» tion:on the surface of the MOON accerleration due to GRAVITY is g/6 the TIME period of SECOND pendulum on earth is 2sec on earth, 2 =2π on moon, T= 2π 6gl dividing the above two equation, we get, T moon = 2 6s |
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