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prove that three consecutive numbers product division by 3 |
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Answer» let the no. be (x) , (x + 1) ,(x + 2).whene a number is divided by 3, the remainder obtained is 0 or 1 or 2.therefore, x = 3n or (3n + 1) or (3n + 2)if x = 3n, then x is divisible by 3if x = 3n + 1 ,then x + 2 = 3n + 1 + 2 = 3n + 3=> x = 3(n + 1) is divisible by 3if x = 3n + 2, then x + 1 = 3n + 2 + 1=> 3n + 3 = 3(n + 1) so, we can say that one of the numbers n,n+ 1 andn+ 2 is always divisible by 3. n(n+ 1) (n+ 2) is divisible by 3. thank you for your answer x=3n+1 then x+1 =_ x=3n+1 then x+1=? l think it's not a correct answer |
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