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Prove that the point (4,-5),(1,1) and(-2,7) are collinear ( by distance formula) |
Answer» ANSWER:-DISTANCE formula isrootover( x2-x1)^2+(y2-y1)^2.Given points are A = (4,-5)B = (1,1)C = (-2,7).1. Distance between AANDB A =(4,-5) = (x1,y1) & B = (1,1) = (x2,y2). = rootover(x2-x1)^2+(y2-y1)^2 = rootover(1-4)^2+(1-(-5))^2 = rootover(-3)^2+(6)^2 = rootover9+36 = rootover45. 2. Distance between BandC B = (1,1) = (x1,y1) & C = (-2,7) = (x2,y2). =rootover(x2-x1)^2+(y2-y1)^2 = rootover(-2-1)^2+(7-1)^2 = rootover(-3)^2+(6)^2 = rootover9+36 = rootover45. 3. Distance between C and A C = (-2,7) = (x1,y1) & A = (4,-5) = (x2,y2). = rootover(x2-x1)^2+(y2-y1)^2 = rootover(4-(-2))^2+(-5-7)^2 = rootover(6)^2+(-12)^2 = rootover36+144 = rootover180 Distance between A and B = Distance between B and C not equal Distance between C and A.Therefore this three points are not collinear.I hope it is helps to you.
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