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Prove that the path of one projectile as seen from another projectile is a straight line. |
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Answer» The coordinates of first projectile as seen from the second projectile are X = x1 - x2 = u1cosθ1 t - u2cosθ2 t X = (u1cosθ1 - u2cosθ2)t Y = y1 - y2 = u1sinθ1 t - 1/2 gt2 - (u2sinθ2 t - 1/2 gt2) Y = (u1 sin θ1 - u2sin θ2)t ∴ = a constant, say m This equation is of the form Y = mX, which is the equation of a straight line. Thus the path of a projectile as seen from another projectile is a straight line. |
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