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Prove that the functionf(x) = 5-3 is continuous at x = 0, at x =-3 and at x = 5. |
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Answer» sir why it's continues at 0 3 -3 for a function to be continuous at any point it should be differentiable at that point and we get 5 by differentiating 5x-3 w.r.t x so it differentiable at every pointalso function should be have some finite value at that point and we get finite values at x=0,3,-3so the function is continuous at these points |
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