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Prove that the function f(x) = logex is strictly increasing on [0, ∞]. |
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Answer» f(x) = ln(x) f’(x) = 1/x for x<0 f’(x) = -ve → increasing for x>0 f’(x) = +ve → decreasing f(x) in increasing when x>0 i.e x∈(0,∞) |
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