1.

Prove that ,tanA+sinA/tanA-sinA=secA+1/secA-1​

Answer»

Answer:

(TANA + sinA)/(tanA - sinA)

=(sinA/cosA + sin A)/(sinA/cosA - sinA)

=((sinA + sinAcosA)/cosA)/((sinA - sinAcosA)/cosA)

=(sinA(1+cosA))/(sinA(1-cosA))

=(1+cosA)/(1-cosA)

=(1+(1/secA))/(1-(1/secA))

=((secA + 1)/secA)/((secA-1)/secA)

=(secA+1)/(secA-1)

Step-by-step EXPLANATION:



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