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Prove that Tan inverse 1/7+ tan inverse 1\8=tan inverse 3\11 |
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Answer» we KNOW that ARC TAN A+arc tan B= arc tan (a+b/1-ab) so, arc tan1/7+arc tan1/8= arc tan (1/7+1/8/1-1/7×1/8) arc tan(7+8/7×8/1-1/56) arc tan(15/56/55/56) arc tan(15/55) arc tan(3/11). |
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