1.

Prove that tan(A+B) + tan C=0

Answer»

A+B+C= 180'
A+B =180'-C
TAN(A+B+C) = tan(180) =0
( tan(a + b) + tan(c)) \div (1 - \tan(a + b) \tan(c) )
=0
=> tan(a+b) + tan(c) =0


Discussion

No Comment Found

Related InterviewSolutions