Prove that tan 6° × tan 21° × tan 30° × tan 69° × tan 84° = 1

1.	Prove that tan 6° × tan 21° × tan 30° × tan 69° × tan 84° = 1/√3
Answer» $\rule{400}4$ ▪︎ *See* *the* *ATTACHMENT* *For* *CORRECT* *Proof. $\rule{400}4$ ▪︎ More* IDs related TRIGONOMETRY:- $\\ \tt\leadsto \tan\theta = \cot(90 - \theta) \\ \\ \tt\leadsto \cot \theta = \tan(90 - \theta) \\ \\ \tt\leadsto \sin\theta = \cos(90 - \theta) \\ \\ \tt\leadsto \cos\theta = \sin(90 - \theta) \\ \\ \tt\leadsto cosec\theta = \sec(90 - \theta) \\ \\ \tt\leadsto \sec\theta = cosec(90 - \theta) \\$ $\rule{400}4$

Prove that tan 6° × tan 21° × tan 30° × tan 69° × tan 84° = 1/√3

Answer»

$\rule{400}4$

▪︎ See the ATTACHMENT For CORRECT Proof.

$\rule{400}4$

▪︎ More IDs related TRIGONOMETRY:-

$\\ \tt\leadsto \tan\theta = \cot(90 - \theta) \\ \\ \tt\leadsto \cot \theta = \tan(90 - \theta) \\ \\ \tt\leadsto \sin\theta = \cos(90 - \theta) \\ \\ \tt\leadsto \cos\theta = \sin(90 - \theta) \\ \\ \tt\leadsto cosec\theta = \sec(90 - \theta) \\ \\ \tt\leadsto \sec\theta = cosec(90 - \theta) \\$

$\rule{400}4$

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Prove that tan 6° × tan 21° × tan 30° × tan 69° × tan 84° = 1/√3

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