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Prove that sine (1 + tane) + cose (1 + cotets. The radii of two concentric circles are 13 cm and 8 cm. AB is a diameter of the bigger circle and BD is aullturde and BD isatangent to the smaller circle touching it at D and intersecting the larger circle at P on producing, Findthe length of APthen prove that&PTS ~ ÎÎĄRQ. |
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Answer» from right triangle BOD BD = √(OB²-OD²) = √(13²- 8²) = √105 from right triangle POD PD = √(OP²-OD²) = √(13²-8²) = √105 PB = BD + PD = 2√105 PB²= 420 from right triangle APB AP = √(AB²- PB²) =√26²- 420 = √676-420 = √256 = 16 cm |
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