1.

Prove that sine (1 + tane) + cose (1 + cotets. The radii of two concentric circles are 13 cm and 8 cm. AB is a diameter of the bigger circle and BD is aullturde and BD isatangent to the smaller circle touching it at D and intersecting the larger circle at P on producing, Findthe length of APthen prove that&PTS ~ ΔΡRQ.

Answer»

from right triangle BOD

BD = √(OB²-OD²) = √(13²- 8²) = √105

from right triangle POD

PD = √(OP²-OD²) = √(13²-8²) = √105

PB = BD + PD = 2√105 PB²= 420

from right triangle APB

AP = √(AB²- PB²) =√26²- 420 = √676-420 = √256 = 16 cm



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