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Prove that sin²theta + cos²theta = 1 |
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Answer» sin^2theta+cos^2theta=1 Step-by-step explanation: in a triangle- a^2+b^2=c^2 = AB^2+BC^2=AC^2 = AB^2/AC^2+BC^2/AC^2=AC^2/AC^2 = AB^2/AC^2+BC^2+AC^2=1 --1 Perpendicular(P)/Hypo(H)=sin THETA Base(B)/Hypo(H)=cos theta from --1 sin ^2 theta + cos^2 theta = 1 |
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