Prove that sin(x+y)/sin(x-y) =tanx+tany/tanx-tany

1.	Prove that sin(x+y)/sin(x-y) =tanx+tany/tanx-tany
Answer» Assin(x+y)=sinxcosy + cosyxsinysin(x-y)=sinxcosy-cosxsinyNow sin(x+y)/sin(x-y)=sinxcosy+cosxsiny/sinxcosy-cosxsinyDividing numerator and denominatory cos x cos y and solving we gettanx + tany/tanx - tanyHope it help u

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