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Prove that: sin"q + cos"6 + 3 sin"e cos26-1 |
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Answer» sin^6ө+cos^6ө =1-3sin^2өcos^2ө(sin^2ө)^3+(cos^2ө)^3= (sin^2ө+cos^2ө)^3− 3 (sin^2ө cos^2ө)(sin^2ө+cos^2ө) [since a + b = (a+b)^3− 3ab(a+b)] = 1 − 3sin^2өcos^2ө [Since sin^2ө+cos^2ө = 1] |
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