1.

Prove that sin(50+Theta) - cos(40- theta) = 0

Answer» LHS,



=>SIN(50+∅) - cos(40-∅)

\cos(theta) = \sin(<klux>90</klux> - theta)


=>Sin(50+∅)- sin{90-(40-∅)}


=>sin(50+∅) - sin{90-40+∅)

=>Sin(50+∅) - sin(50+∅)

=0

RHS,

=> 0

---------------------

0=0
LHS=RHS



I hope this will help you


-by ABHAY


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