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Prove that sin ^3 theta+cos^3theta/sin theta +cos theta=1-sin theta *cos theta |
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Answer» ERS: USE the IDENTITY (a^3+b^3)= (a+b)(a^2+b^2-ab) sin^3A + COS^3A÷(sinA +cos ). + sinA.cosA (sinA+cosA)(sin^2+cos^2 -sinA.cosA)÷ (sinA + cosA)+ sinA.cosA or( sinA^2+cosA^2 -sinA.cosA) +sinA.cosA 1-sinA.cosA+sinA.cosA 1 |
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