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Prove that sin^2 18°+cos^² 36°=3/4 |
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Answer» We can also do this without actually knowing the values sin18°=√5-1/4 & cos36°=√5+1/4 putting this values above we get (√5-1/4)^2+(√5+1/4)^2=3/4 sin18°=√5_1/4 & cos36°=√5+1/4 putting this values above we get (√5-1/4)^2+(√5+1/4)^2 =3/4 |
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