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Prove that Sec2 θ+ Coser θ24Sec" θ+ Cosec |
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Answer» f(x)=sec^2x+cosec^2x=(1/cos^2x)+(1/sin^2x) =(sin^2x+cos^2x)/(sin^2x.con^2x)=1/(sin^2x.cos^2x) =1/(sinx.cosx)^2 =4/sin2x sin2x<=1 => f(x)>=4 pls write on paper |
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