Prove that: sec θ+tan θ-1tan θ-sec θ+1=cos θ1-sin θ

1.	Prove that: sec θ+tan θ-1tan θ-sec θ+1=cos θ1-sin θ
Answer» Prove that: $\frac{\sec θ + \tan θ - 1}{\tan θ - \sec θ + 1} = \frac{\cos θ}{1 - \sin θ}$

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