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Prove that sec A.root 1-sin^A=1 |
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Answer» er: Step-by-step EXPLANATION: SecA.√ 1- sin²A= 1 ( cos²A +sin²A =1 cos²A = 1 - sin²A COSA = √ 1 - sin²A) Solving LHS:- 1/cos × cos = 1 ( cos²A +sin²A = 1 cosA = √ 1 - sin²A) Hence, LHS = RHS |
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