1.

Prove that S2n+1 = (2n+1)an+1​

Answer»

ong>ANSWER:

Solution :

S1S2=2n+1n+1

Sn=an+n(n−1)2⋅d

S1=a+(2n+11)+(2n+1−1)d2=[2n+1][a+nd=−(1)

NUMBER of terms in S2=n+1

S2=(n+1)a+(n+1)(n+1−1)2(2D)=(n+1)a+(n+1)nd

=(n+1)(a+nd)

S1S2=[2n+1][a+nd][n+1][a+nd]=2n+1n+1.

Step-by-step explanation:

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