Prove that roots of the equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 ar – InterviewSolution

1.	Prove that roots of the equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are always real and can be equal unless a=b=c
Answer» Prove that roots of the equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are always real and can be equal unless a=b=c

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