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Prove that n3- n is divisible by 24 for any odd n​

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Answer:

Q: Prove by induction that n3−n is DIVISIBLE by 24 for all odd positive integers

After proving the FIRST part for n=1

Assume TRUE for some positive integer n=k

ie k3−k=24x where x is an integer

Prove true for n=k+2

ie (k+2)3−(k+2)=24y where y is an integer

=k3+6k2+11k+6

=24x+12k+6k2+6 But how do I get this in the form 24y? Am i supposed to use 2k+1 instead?

Step-by-step explanation:

PLZ mark me as brainliest



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