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Prove that n3- n is divisible by 24 for any odd n |
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Answer» Answer: Q: Prove by induction that n3−n is DIVISIBLE by 24 for all odd positive integers After proving the FIRST part for n=1 Assume TRUE for some positive integer n=k ie k3−k=24x where x is an integer Prove true for n=k+2 ie (k+2)3−(k+2)=24y where y is an integer =k3+6k2+11k+6 =24x+12k+6k2+6 But how do I get this in the form 24y? Am i supposed to use 2k+1 instead? Step-by-step explanation: PLZ mark me as brainliest |
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