Prove that n(AUBUC) =n(A)+n(B)+n(C)-n(AUB)-n(BUC)-n(AUC)+n(AnBnC).

1.	Prove that n(AUBUC) =n(A)+n(B)+n(C)-n(AUB)-n(BUC)-n(AUC)+n(AnBnC).
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