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prove that in a parallelogram the inspectors of any two consecutive angles intersect at right angles. |
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Answer» Step-by-step EXPLANATION: Let ABCD is a parallelogram as we know ∠A+∠B=180
OAbisects∠DAB&OBbisects∠CBA toprove∠AOB=90 0
nowinΔAOB ∠OAB+∠CBA+∠AOB=180 0
2 1
∠DAB+ 2 1
∠CBA+∠AOB=180 0
2 1
(∠DAB+CBA)+∠AOB=180 0
2 1
×180 0 +∠AOB=180 0
90 0 +∠AOB=180 0
∠AOB=180 0 −90 0
∠AOB=90 0
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