Prove that:(i) tan 4π-cos3π2-sin5π6cos2π3=14(ii) sin13π3sin8π3+cos2π3sin5π6=12(iii) sin 13π3sin2π3+cos4π3sin13π6=12(iv) sin10π3cos13π6+cos8π3sin5π6=-1(v) tan5π4cot9π4+tan17π4cot15π4=0

Prove that:(i) tan 4π-cos3π2-sin5π6cos2π3=14(ii) sin13π3sin8π3+c

1.	Prove that:(i) tan 4π-cos3π2-sin5π6cos2π3=14(ii) sin13π3sin8π3+cos2π3sin5π6=12(iii) sin 13π3sin2π3+cos4π3sin13π6=12(iv) sin10π3cos13π6+cos8π3sin5π6=-1(v) tan5π4cot9π4+tan17π4cot15π4=0
Answer» Prove that: (i) $\tan 4 π - \cos \frac{3 π}{2} - \sin \frac{5 π}{6} \cos \frac{2 π}{3} = \frac{1}{4}$ (ii) $\sin \frac{13 π}{3} \sin \frac{8 π}{3} + \cos \frac{2 π}{3} \sin \frac{5 π}{6} = \frac{1}{2}$ (iii) $\sin \frac{13 π}{3} \sin \frac{2 π}{3} + \cos \frac{4 π}{3} \sin \frac{13 π}{6} = \frac{1}{2}$ (iv) $\sin \frac{10 π}{3} \cos \frac{13 π}{6} + \cos \frac{8 π}{3} \sin \frac{5 π}{6} = - 1$ (v) $\tan \frac{5 π}{4} \cot \frac{9 π}{4} + \tan \frac{17 π}{4} \cot \frac{15 π}{4} = 0$

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Prove that:(i) tan 4π-cos3π2-sin5π6cos2π3=14(ii) sin13π3sin8π3+cos2π3sin5π6=12(iii) sin 13π3sin2π3+cos4π3sin13π6=12(iv) sin10π3cos13π6+cos8π3sin5π6=-1(v) tan5π4cot9π4+tan17π4cot15π4=0

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