Prove that: (i) a+b+ca−1b−1+b−1c−1+c−1a−1=abc (ii) (a−1+

1.	Prove that: (i) a+b+ca−1b−1+b−1c−1+c−1a−1=abc (ii) (a−1+b−1)−1=aba+b
Answer» Prove that: (i) $\frac{a + b + c}{a^{- 1} b^{- 1} + b^{- 1} c^{- 1} + c^{- 1} a^{- 1}} = a b c$ (ii) $(a^{- 1} + b^{- 1})^{- 1} = \frac{a b}{a + b}$

Prove that: (i) a+b+ca−1b−1+b−1c−1+c−1a−1=abc (ii) (a−1+b−1)−1=aba+b

Answer»

Prove that:

(i) $\frac{a + b + c}{a^{- 1} b^{- 1} + b^{- 1} c^{- 1} + c^{- 1} a^{- 1}} = a b c$

(ii) $(a^{- 1} + b^{- 1})^{- 1} = \frac{a b}{a + b}$