Prove that:(i) 3×5-3 ÷ 3-13 5×3×566=35(ii) 93/2-3×50-181-1/2 = 15(iii) 14-2-3×82/3×40+916-1/2 = 163(iv) 21/2×31/3×41/410-1/5×53/5 ÷ 34/3×5-7/54-3/5×6=10(v) 14 +(0.01)-1/2-(27)2/3 =32(vi) 2n + 2n -12n+1-2n=32(vii) 64125-2/3 + 12566251/4 + 25643 = 6516(viii) 3-3×62×9852×1/253×(15)-4/3×31/3=282(ix) (0.6)0-(0.1)-138-1323+-13-1=-32

Prove that:(i) 3×5-3 ÷ 3-13 5×3×566=35(ii) 93/2-3×50-181-1/2 = 15

1.	Prove that:(i) 3×5-3 ÷ 3-13 5×3×566=35(ii) 93/2-3×50-181-1/2 = 15(iii) 14-2-3×82/3×40+916-1/2 = 163(iv) 21/2×31/3×41/410-1/5×53/5 ÷ 34/3×5-7/54-3/5×6=10(v) 14 +(0.01)-1/2-(27)2/3 =32(vi) 2n + 2n -12n+1-2n=32(vii) 64125-2/3 + 12566251/4 + 25643 = 6516(viii) 3-3×62×9852×1/253×(15)-4/3×31/3=282(ix) (0.6)0-(0.1)-138-1323+-13-1=-32
Answer» Prove that: (i) $\sqrt{3 \times 5^{- 3}} \div \sqrt[3]{3^{- 1}} \sqrt{5} \times \sqrt[6]{3 \times 5^{6}} = \frac{3}{5}$ (ii) $9^{3 / 2} - 3 \times 5^{0} - {(\frac{1}{81})}^{-}^{1 / 2} = 15$ (iii) ${(\frac{1}{4})}^{- 2} - 3 \times 8^{2 / 3} \times 4^{0} + {(\frac{9}{16})}^{- 1 / 2} = \frac{16}{3}$ (iv) $\frac{2^{1 / 2} \times 3^{1 / 3} \times 4^{1 / 4}}{10^{- 1 / 5} \times 5^{3 / 5}} \div \frac{3^{4 / 3} \times 5^{- 7 / 5}}{4^{- 3 / 5} \times 6} = 10$ (v) $\sqrt{\frac{1}{4} + (0.01)^{- 1 / 2}} - (27)^{2 / 3} = \frac{3}{2}$ (vi) $\frac{2^{n} + 2^{n - 1}}{2^{n + 1} - 2^{n}} = \frac{3}{2}$ (vii) ${(\frac{64}{125})}^{- 2 / 3} + \frac{1}{{(\frac{256}{625})}^{1 / 4}} + (\frac{\sqrt{25}}{\sqrt[3]{64}}) = \frac{65}{16}$ (viii) $\frac{3^{- 3} \times 6^{2} \times \sqrt{98}}{5^{2} \times \sqrt[3]{1 / 25} \times (15) -^{4 / 3} \times 3^{1 / 3}} = 28 \sqrt{2}$ (ix) $\frac{(0.6)^{0} - (0.1) - 1}{{(\frac{3}{8})}^{- 1} {(\frac{3}{2})}^{3} + {(- \frac{1}{3})}^{- 1}} = - \frac{3}{2}$