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Prove that equal chords of a circle are equidistant from the centre.​

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Answer:

Step-by-step EXPLANATION:

Chords which are equidistant from the centre are equal in LENGTH. GIVEN: Two chords AB and CD of a circle which are equidistant from centre O i.e., OL = OM, where OL PERPENDICULAR to AB and OM perpendicular to CD. TO PROVE: AB = CD. CONSTRUCTION: Join OA and OC. or, AB = CD. Hence Proved. Was this answer helpful?



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