Prove that:-cosecA + 1 ÷ cosecA - 1 = sec A + tan A

1.	Prove that:-cosecA + 1 ÷ cosecA - 1 = sec A + tan A
Answer» Step-by-step EXPLANATION: ( cosecA +1)/(COSEC A - 1) = (secA+tanA)^2 L.H.S. =( 1/sinA +1)/( 1/sinA - 1) =(1+sinA) /(1-sinA). =(1+sinA)×(1+sinA)/(1-sinA)×(1+sinA) =(1+sinA)^2/(1-sin^2A) =(1+sinA)^2/cos^2A. =(1/cosA+sinA/cosA)^2 =(secA+tanA)^2 ,proved. Hope U understand mark me as BRAINLEAST

Answer»

Step-by-step EXPLANATION:

( cosecA +1)/(COSEC A - 1) = (secA+tanA)^2

L.H.S.

=( 1/sinA +1)/( 1/sinA - 1)

=(1+sinA) /(1-sinA).

=(1+sinA)×(1+sinA)/(1-sinA)×(1+sinA)

=(1+sinA)^2/(1-sin^2A)

=(1+sinA)^2/cos^2A.

=(1/cosA+sinA/cosA)^2

=(secA+tanA)^2 ,proved.

Hope U understand mark me as BRAINLEAST

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Prove that:-cosecA + 1 ÷ cosecA - 1 = sec A + tan A​

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Prove that:-cosecA + 1 ÷ cosecA - 1 = sec A + tan A