1.

Prove that angles opposite to equal sides of an isosceles triangle are equal.please give the proof ​

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Answer:

Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D

Now in triangles ABD and ACD We have AB=AC (Given)

∠BAD=∠CAD (because AD is bisector of ∠A

AD=AD (Common side)

Therefore by SAS congruence CONDITION we have

△ABC≅△ACD

⇒∠B=∠C

(Corresponding parts of congruent triangles are equal ).

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