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Prove that angles opposite to equal sides of an isosceles triangle are equal.please give the proof |
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Answer» Answer: Let △ABC be an isosceles triangle such that AB =AC Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D Now in triangles ABD and ACD We have AB=AC (Given)∠BAD=∠CAD (because AD is bisector of ∠A AD=AD (Common side) Therefore by SAS congruence CONDITION we have△ABC≅△ACD ⇒∠B=∠C (Corresponding parts of congruent triangles are equal ).ĦØP€ IŦŞ Ħ€ŁP ¥ØỮ |
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