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Prove that 5 root 2 in irrigation number |
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Answer» Answer: Let
be a rational number. then it must be in form of q p
where, q =0 ( p and q are co-prime) 5
= q p
5
×q=p Suaring on both SIDES, 2 =p 2 --------------(1) p 2 is divisible by 5. So, p is divisible by 5. p=5c Suaring on both sides, p 2 =25c 2 --------------(2) Put p 2 in eqn.(1) 5q 2 =25(c) 2
q 2 =5c 2
So, q is divisible by 5. . Thus p and q have a common factor of 5. So, there is a contradiction as PER our assumption. We have assumed p and q are co-prime but here they a common factor of 5. The above statement contradicts our assumption. Therefore, 5
is an irrational number. |
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