1.

Prove that√3is an irrational number. ​

Answer» RONG>To PROVE:-

\bf\implies √3 \: is \: irrational

SOLUTION:-

\bf\implies By \: Contradiction\: Method

\bf\implies Assuming \: √3 is \: rational

\bf\implies √3=\frac{p}{q} \: [p \: and \: q \: are \: co-prime

\bf\implies p=√3q \: ..(1)

\bf\implies p²=3q²

\bf\implies \frac{p²}{3}=q²

\bf\implies p² \: divides \: 3

\bf\implies p \: also \: divides \: 3

\bf\implies p=3m \: [m \: is \: any \: integer]

\bf\implies √3q=3m

\bf\implies  q=\frac{3m}{√3}

\bf\implies q=√3m

\bf\implies q²=3m²

\bf\implies \frac{q²}{3}=m²

\bf\implies q² \: divides\: 3

\bf\implies q \: divides \: 3

\bf\implies p  \: divides \: 3

\bf\implies q \: also \: divides \: 3

\bf\implies But \: p \:  and \: q \: are \: co-primes

\bf\implies This \: is \: because \: of \: our \: wrong \: assumption

\bf\implies √3 \: is \: irrational



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