Prove that 3- (minus)√(root)5 is an irrational number.

1.	Prove that 3- (minus)√(root)5 is an irrational number.
Answer» If we are known with √5 is irrational than it can be proved as: Let 3 - √5 be a rational number 3 - √5 = p/q [ where p and q are integer , q ≠ 0 and q and p are co-prime number ] => √5 = 3 - p/q => √5 = (3q - p)/q We know that number of form p/q is a rational number. So, √5 is also a rational number. But we know that √5 is irrational number. This contradicts our assumption. Therefore, 3 - √5 is an irrational number.

Answer»

If we are known with √5 is irrational than it can be proved as:

Let 3 - √5 be a rational number

3 - √5 = p/q [ where p and q are integer , q ≠ 0 and q and p are co-prime number ]

=> √5 = 3 - p/q

=> √5 = (3q - p)/q

We know that number of form p/q is a rational number.

So, √5 is also a rational number.

But we know that √5 is irrational number. This contradicts our assumption.

Therefore, 3 - √5 is an irrational number.

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Prove that 3- (minus)√(root)5 is an irrational number.

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